Program for Armstrong Number in C++

Here you will get the program for Armstrong number in C++.

A number whose total of digits raised to control n is equivalent to itself is called Armstrong number. Here n is the absolute digits in the number.

For instance, 153 is armstrong number as 153 = 1³ + 5³ + 3³ = 1 + 125 +27.

Program

#include<iostream>
#include<math.h>
 
using namespace std;
 
int main()
{
	int n,m=0,p=0,x,y;
	cout<<"Enter any number: ";
	cin>>n;
 
	y=n;
	
	while(y!=0){
		y=y/10;
		p++;
	}
	
	y=n;
	
	while(n!=0)
	{
		x=n%10;
		m+=pow(x,p);
		n=n/10;
	}
	
	if(y==m)
		cout<<"The given number is an armstrong number";
	else
		cout<<"The given number is not an armstrong number";
 
	return 0;
}

Output

Enter any number: 9
The given number is an armstrong number