In this instructional exercise, we will figure out how to discover the x-catch and y-block of the line going through the given two-point in the Python programming language?

The x-catch is where the line cut the x-pivot and the y-block of the line is where the line will cut the y-hub. As we as a whole have learned in the organize geometry that how we discover the x-block and y-capture of the given line and furthermore in this instructional exercise we will utilize a similar idea that we have learned in the arrange geometry. Here, the facilitate of two will be given by the client by which the line passes. To take care of this issue, the thought is basic that at first discover the condition of the line by utilizing the scientific recipe y = m*x+c where m is the slant of the line and c is steady. After this to know the x-catch of the line simply put the estimation of y is zero and the relating estimation of x will be x-capture and comparably for y-block simply put the estimation of x is zero and the relating estimation of y will be y-block. Prior to going to tackle this issue, we will the calculation and attempt to comprehend the methodology.

The calculation to take care of this issue:

Take the facilitate of the two-point by the client from which the line will pass.

Discover the slant of the line by utilizing the equation m = (y2-y1)//(x2-x1).

Presently, compose the condition of the line by utilizing the scientific equation y = m*x+c where c is steady.

To discover the estimation of steady c simply put the given one point arrange in the statement of the line i.e y = m*x+c.

Here, to know the x-capture simply put the estimation of y is zero in the condition of the line.

Likewise to discover the y-capture simply put the estimation of x is zero in the outflow of the line.

Print the estimation of x-catch and y-capture of the line.

Presently, we will compose the Python program by executing the above calculation in a basic manner.

```
a,b,p,q=map(int,input('Enter the coordinates of the points:').split())
m=(q-b)/(p-a)
y=b
x=a
c=y-(m*x)
#to find x-intercept.
y=0
x=(y-c)/m
print('x-intercept of the line:',x)
#to find y-intercept.
x=0
y=(m*x)+c
print('y-intercept of the line:',y)
```

### Output:

```
Enter the coordinates of the points: 5 2 2 7
The x-intercept of the line: 6.2
The y-intercept of the line: 10.333333333333334
```