Python program to check whether a given number is a Fibonacci number or not

Checking Fibonacci number in Python: Here, we will realize whether a given number is a Fibonacci number or not utilizing Python program?

Given a number and we need to check whether it is a Fibonacci number or not in Python?

Checking Fibonacci number

Consider the given Fibonacci arrangement with an initial not many terms: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, etc…

There is a well-known recipe to check whether a given number is a Fibonacci number or not? (5n2 + 4) or (5n2 – 4)

In the event that the aftereffect of this recipe is an ideal square, at that point, the number will be a Fibonacci number.

Example:

    Input: 
    num = 13
    Output:
    Yes, 13 is a Fibonacci number

    Input: 
    num = 143
    Output:
    No, 144 is not a Fibonacci number

Python program to check Fibonacci number

# python program to check if given
# number is a Fibonacci number

import math

# function to check perferct square
def checkPerfectSquare(n):
    sqrt = int(math.sqrt(n))
    if pow(sqrt, 2) == n:
        return True
    else:
        return False

# function to check  Fibonacci number
def isFibonacciNumber(n):
    res1 = 5 * n * n + 4
    res2 = 5 * n * n - 4
    if checkPerfectSquare(res1) or checkPerfectSquare(res2):
        return True
    else:
        return False

# main code
num = int(input("Enter an integer number: "))

# checking
if isFibonacciNumber(num):
    print ("Yes,", num, "is a Fibonacci number")
else:
    print ("No,", num, "is not a Fibonacci number")

Output:

First run:
Enter an integer number: 13
Yes, 13 is a Fibonacci number

Second run:
Enter an integer number: 144
Yes, 144 is a Fibonacci number

Third run:
Enter an integer number: 143
No, 143 is not a Fibonacci number