Here, we will figure out how to discover the arrangement of a given uncommon aggregate arrangement in Python?
We are going to structure an uncommon aggregate arrangement work which has the following attributes:
f(0) = 0
f(1) = 1
f(2) = 1
f(3) = 0
f(x) = f(x-1) + f(x-3)
Python arrangement of the above entirety arrangement:
# function to find the sum of the series
def summ(x):
if x == 0:
return 0
if x == 1:
return 1
if x == 2:
return 1
if x == 3:
return 0
else:
return summ(x-1) + summ(x-4)
# main code
if __name__ == '__main__':
# finding the sum of the series till given value of x
print("summ(0) :", summ(0))
print("summ(1) :", summ(1))
print("summ(2) :", summ(2))
print("summ(3) :", summ(3))
print("summ(10):", summ(10))
print("summ(14):", summ(14))
Output:
summ(0) : 0
summ(1) : 1
summ(2) : 1
summ(3) : 0
summ(10): 5
summ(14): 17