Python Find the factorial of a number using recursion

Factorial in Python: Here, we will figure out how to locate the factorial of a given number utilizing the recursion in Python? Given a whole number and we need to locate the factorial of the number utilizing recursion in Python. Example: Input: num = 3 Output: Factorial of 3 is: 6 #3! = 3x2x1 = 6 Note: Factorial of 0 and 1 will be 1 Program # Python code to find factorial using recursion # recursion function definition # it accepts a number and returns its factorial def factorial(num): # if number is negative - print error if num < 0: print("Invalid number...") # if number is 0 or 1 - the factorial is 1 elif num == 0 or num == 1: return 1 else: # calling function itself i.e. recursive return num * factorial(num - 1) # main code if __name__ == '__main__': #input the number x = int(input("Enter an integer number: ")) print("Factorial of ", x, " is = ", factorial(x)) x = int(input("Enter another integer number: ")) print("Factorial of ", x, " is = ", factorial(x)) x = int(input("Enter another integer number: ")) print("Factorial of ", x, " is = ", factorial(x)) Output Enter an integer number: 5 Factorial of 5 is = 120 Enter another integer number: 0 Factorial of 0 is = 1 Enter another integer number: -3 Invalid number... Factorial of -3 is = None